Monday, April 29, 2013
Sunday, April 14, 2013
EMS not retrieving records with decimal on windows 7
If you have installed EMS SQL manager lite 2011 on windows 7 and when you execute a select command in it and it gives this following BCD error then this article will help you to fix this.
Go to the windows control panel and in there open the Regional settings and further click Additional settings.
in there select Decimal symbol= . instead of ,
restart the EMS and the Query will work fine.
Sunday, April 7, 2013
Saturday, June 9, 2012
Sunday, March 4, 2012
Database Procedure (For Bank application) to create Records for test environment.
CREATE PROCEDURE [dbo].[SP_InsertTestData]
AS
BEGIN
SET NOCOUNT ON
SET XACT_ABORT ON
INSERT INTO [User] ([UserName], [Password], [Email], [Role], [DisplayName], [Verified]) VALUES ('RAHUL','RAHUL','dummy@domain.ext','SystemIntegrator','RAHUL', 1)
INSERT INTO dbo.[CARDCONTROL]( [Name], [EmailForAlerts], SystemIntegratorId) VALUES ( 'My First CARDCONTROL', 'RAHUL_test@serverTT2.com', (Select Id from [dbo].[User] where UserName = 'RAHUL' ));
INSERT INTO dbo.GOLDCARDCONTROL( Name, Serial, [Type], CARDControlnumber, ChipId, MaximumCARDControlLimit, BranchID) VALUES ( 'TestUser 1', '1178189980', 'STANDARDCHARTEDGBP', '321082.50.107', 9600, 2.0, (Select Id from dbo.Logins where NAME='Securelogins'));
INSERT INTO dbo.GOLDCARDCONTROL( Name, Serial, [Type], CARDControlnumber, ChipId, MaximumCARDControlLimit, BranchID) VALUES ( 'TestUser 2', '1178189981', 'STANDARDCHARTEDGBP', '321082.50.107', 9600, 2.0, (Select Id from dbo.Logins where NAME='Securelogins2'));
INSERT INTO dbo.GOLDCARDCONTROL( Name, Serial, [Type], CARDControlnumber, ChipId, MaximumCARDControlLimit, BranchID) VALUES ( 'TestUser 3', '1178189982', 'STANDARDCHARTEDGBP', '321082.50.107', 9600, 2.0, (Select Id from dbo.Logins where NAME='Securelogins3'));
INSERT INTO dbo.GOLDCARDCONTROL( Name, Serial, [Type], CARDControlnumber, ChipId, MaximumCARDControlLimit, BranchID) VALUES ( 'TestUser 4', '1178189983', 'STANDARDCHARTEDGBP', '321082.50.107', 9600, 2.0, (Select Id from dbo.Logins where NAME='Securelogins4'));
INSERT INTO dbo.GOLDCARDCONTROL( Name, Serial, [Type], CARDControlnumber, ChipId, MaximumCARDControlLimit, BranchID) VALUES ( 'TestUser 5', '1178189984', 'STANDARDCHARTEDGBP', '321082.50.107', 9600, 2.0, (Select Id from dbo.Logins where NAME='Securelogins5'));
INSERT INTO dbo.GOLDCARDCONTROL( Name, Serial, [Type], CARDControlnumber, ChipId, MaximumCARDControlLimit, BranchID) VALUES ( 'TestUser 6', '1234560', 'STANDARDCHARTEDGBP', '321082.50.107', 9600, 2.0, (Select Id from dbo.Logins where NAME='Securelogins6'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (1, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189980'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (2, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189980'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (3, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189980'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (4, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189980'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (1, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189981'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (2, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189981'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (3, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189981'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (4, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189981'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (1, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189982'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (2, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189982'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (3, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189982'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (4, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189982'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (1, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189983'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (2, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189983'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (3, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189983'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (4, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189983'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (1, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189984'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (2, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189984'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (3, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189984'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (4, (Select Id from dbo.GOLDCARDCONTROL where Serial='1178189984'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (1, (Select Id from dbo.GOLDCARDCONTROL where Serial='1234560'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (2, (Select Id from dbo.GOLDCARDCONTROL where Serial='1234560'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (3, (Select Id from dbo.GOLDCARDCONTROL where Serial='1234560'));
INSERT INTO dbo.SAVINGSACCOUNT([Sequence], GOLDCARDCONTROLId) VALUES (4, (Select Id from dbo.GOLDCARDCONTROL where Serial='1234560'));
END
Sunday, November 13, 2011
Data entry when IDENTITY_INSERT is set to OFF.
If you get an error message while inserting records in a table.
Error message looks like : Cannot insert explicit value for identity column in table ‘dbo.InverterData’ when IDENTITY_INSERT is set to OFF.
to fix this ; SET IDENTITY_INSERT dbo.InverterData ON; before insert command and after insert enter this: SET IDENTITY_INSERT dbo.InverterData OFF;
SET IDENTITY_INSERT dbo.InverterData ON;
INSERT INTO dbo.InverterData
( Id, CurrentL1, CurrentL2, CurrentL3, GridFrequency, Power, SampleTime, Temperature, TotalEnergy, TotalEnergyToday, TotalHours, InverterId )
VALUES ( 5, 33, 43, 53,8,68,21/11/2011 13:00:00,210,2 );
SET IDENTITY_INSERT dbo.InverterData OFF;
GO
Thursday, July 7, 2011
Scrum tool - iceScrum (Agile product development) used for test driven development.
Sand box for collecting user stories.
here in image below you see the user stories defined after meeting with team. Product owner can view the page online and provide comments over priority of a user story and can ask team to shift a user story to later sprint or add a user story to current sprint. Keeping the product owner in loop from the first day. this helps to keep transparency and structure in the planned tasks and priorities.
the image below shows how some acceptance test cases are written of each story to ensure that what understood related to the user story is correct. Team can review the test cases and developers can even use it as a checklist before asking testes to test the user story. Moreover the product owner can check if the team understood what he wanted in the user story and all people are on same understanding level. Any feedback can be provided and further this can be used to revise a user story or add a reminder or exceptions to be specific on to what is expected and what is agreement with product owner and what is delivered.
tabular form of sandbox.
product backlog,
tabular form of product backlog
sprint3 log view
Sprint Plan.
tabular form sprint plan
burn down in hours
Burndown in stories.
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